(3x-1)^2-8(x+1)^2=(x+2)(x-2)

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Solution for (3x-1)^2-8(x+1)^2=(x+2)(x-2) equation: 



(3x-1)^2-8(x+1)^2=(x+2)(x-2)

We move all terms to the left:

(3x-1)^2-8(x+1)^2-((x+2)(x-2))=0

We use the square of the difference formula

x^2+(3x-1)^2-8(x+1)^2+4=0

We move all terms containing x to the left, all other terms to the right

x^2+(3x-1)^2-8(x+1)^2=-4

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